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如圖,在同一平面內,將△ABC繞點A旋轉到△AED的位置,若AE⊥BC,∠ADC=65°,則∠ABC的度數為(...

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問題詳情:

如圖,在同一平面內,將△ABC繞點A旋轉到△AED的位置,若AE⊥BC,∠ADC=65°,則∠ABC的度數為(...

如圖,在同一平面內,將△ABC繞點A旋轉到△AED的位置,若AE⊥BC,∠ADC=65°,則∠ABC的度數為(  )                                                                                     

                                                                      

A.30°                              B.40°                               C.50°                               D.60°

【回答】

B【考點】旋轉的*質.                                                                                     

【分析】先根據旋轉的*質得AD=AC,∠BAE=∠CAD,再根據等腰三角形的*質和三角形內角和計算出∠CAD=50°,則∠BAE=50°,然後利用互餘計算∠ABC的度數.                                                        

【解答】解:∵△ABC繞點A旋轉到△AED的位置,                                            

∴AD=AC,∠BAE=∠CAD,                                                                                 

∵AD=AC,                                                                                                        

∴∠ACD=∠ADC=65°,                                                                                     

∴∠CAD=180°﹣65°﹣65°=50°,                                                                           

∴∠BAE=50°,                                                                                                   

∵AE⊥BC,                                                                                                       

∴∠ABC=90°﹣∠BAE=40°.                                                                                 

知識點:圖形的旋轉

題型:選擇題

標籤:abc aed 繞點 BC AE